问题41.细胞木匠

join doesn't work here?

超级简单

thanks!

这将是单个内置功能的复制。

有趣的！

Assertion fails in Cody even though the assertion passes in MATLAB R2014b. Does any one know why?

Hi. The assertion could only have passed outside of Cody if the wrong "correct solution" were specified for comparison, and this would happen if you copy the HTML-rendered text — due to a kind of bug in the way the solution vector is displayed on the Cody webpage (better: copy from the HTML _source code_). -----
The correct solution has delimiters (here shown as ^ for clarity) as in 'this^one^^has^ ^some tricky^stuff', whereas your code produces 'this^one^has^some tricky^stuff', so you don't get the correct result between "one" and "has", nor between "has" and "some".

我认为必须检查测试2。

I compared the test 2 correct answer with the program output using strcmp, and it gave 1 as output.( This was before introducing the program lines which also take into consideration the single space given in 5th element of in_cell in test 2)

任何已经解决或有想法解决的人，请让我知道我程序中的错误是什么。

顺便说一句，谢谢，程序可能有点冗长。

THE TEST CASE 2 OUTPUT YOU HAVE DISPLAYED IS WRONG
更正它。

这里有两个问题：
(1) The HTML display in Cody automatically only displays a single space. Therefore, while the solution *vector* _specified_ as the answer to Test 2 in Cody is correct, the *text* that is _displayed_ is not. You can confirm that the correct information was specified by viewing the HTML source. It is unfortunate that this is not displayed correctly. Of course, any results should match the solution, not the incorrect display.
(2) Your candidate solution fails because it is incorrect. Even if it matches the HTML-parsed display, it doesn't match the true specified solution vector. To make this apparent, imagine if delim='^' (no other changes). The correct solution to Test 2 would then be 'this^one^^has^ ^some tricky^stuff', whereas your output would be 'this^one^has^ ^some tricky^stuff' (provided in Solution 1280078). In other words, you needed a double space between "one" and "has".

My solution is:
函数out_str = celltr_joiner（in_cell，delim）
y=in_cell;
y(find(cellfun(@isempty,cellfun(@strtrim,y,'UniformOutput',false))))=[];
out_str = strjoin(y);
out_str(find(out_str==' '))=delim;
end
在MATLAB上，所有测试通过，但在Cody网站上第二个测试失败！

This code is working as expected in MATLAB command window. can i know why it is failed here

why deblank?

ok, is not really elegant not short, but it's correct. why doesn't it pass the test?

问题是您的输出是单元字符串，而不是字符数组。您可以通过添加out_str = char（out_str）获得一个char数组;最后，或从开始使用in_cell {1}和in_cell {i}而不是in_cell（1）和in_cell（i）来使用char数组。

I think there is something wrong here, this solution seems to work.

很好，我从未听说过这个！

I had tried this, but kept getting: "strjoin not found" on my workstation :(
So I had to work around it.

最好的！（没有Str Join）

answers just the test suite...

有更好的作弊方法！

Simple and easy to understand, and works in versions before strjoin appeared.

gh，循环！

printf works wonders

哇！杰出的！