基于斯坦的回答,改变问题解决一阶形式,如下
信谊h (t) m c k h0 dh0 C10 C11
Dh (t) = diff (h (t), t);
方程式= m * diff (h (t), t, t) = = - c * Dh-k * h (t);
%索尔= dsolve(方程式,h (0) = = h0 Dh (0) = = dh0);
var = (h (t));
[eqs1st, vars1st newVars1st] = reduceDifferentialOrder(方程式一样,var);
sol1st = dsolve (eqs1st h (0) = = h0 Dh (0) = = dh0);