问题1740查找号码模式在矩阵的行...

由...制作克里斯·E.

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{ “关系”：[{ “关系”： “http://schemas.mathworks.com/matlab/code/2013/relationships/document”， “targetMode”： “”， “relationshipId”： “RID1”，“目标“：” /matlab/document.xml “}，{” 关系 “：” http://schemas.mathworks.com/matlab/code/2013/relationships/output”， “targetMode”： “”， “relationshipId”：“RID2”， “目标”： “/ MATLAB /的Output.xml”}]， “份”：[{ “partUri”： “/ MATLAB / document.xml中”， “关系”：[] “的contentType”：”应用/ vnd.mathworks.matlab.code.document + xml “的， ”内容“： ”<XML版本= \“ 1.0 \” 编码= \ “UTF-8 \”？> \ n <W：文件的xmlns：瓦特= \ “HTTP：//schemas.openxmlformats.org/wordprocessingml/2006/main \”> <W：体> <W：p> <W：PPR> <瓦特：PSTYLE瓦特：VAL = \ “文本\”/> </ W：PPR> <W，R> <W：T>所以我觉得这可能是一个很难，可它只是对我来说很难因此，这里是它是什么，我会给出一个矩阵，由5列的一些数目的行，以使其更简单我将不重复在</ W：T>任何数目的</ W：R> <W：R> <W：T> </ W：T> </瓦特：R> <W：R> <W：RPR> <W：b /> </ W：RPR> <W：T>单排</ W：T> </ W：R> <W：R><W：T>，所以在</所有数字瓦特：T> </ W：R> <W：R> <W：T> </ W：T> </ W：R> <W：R> <W：RPR> <W：B /> </ w的：RPR> <W：T>单排</ W：T> </ W：R> <W：R> <W：T>是唯一的。所以，你需要找到一个被发现在最多2个，3个或4个数字一</ W：T> </ W，R> <W，R> <W：T> </ W：T> </ W：R> <W：R> <W：RPR> <W：b /> </ W：RPR> <W：T>单排</ W：T> </ W：R> <W：R> <W：T>在于重复</ W：T> </ W：R> <W：R> <W：T> </ W：T> </ W：R> <W：R> <W：RPR><W：b /> </ W：RPR> <W：T>其他行</ W：T> </ W：R> <W：R> <W：T>和的倍量他们在一个重复给定矩阵。 To make it a little better, you only need to display the rows/numbers that repeat at lease twice or more. Examples are the best way to show what to do:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ %p is the given matrix\n p = [1 2 3 4 5;\n 2 3 4 5 1;\n 3 4 6 7 8;\n 1 2 4 3 5;\n 4 6 3 2 1];\n %v is the amount of elements per row that are being checked to see if they repeat in another row\n v = 4;\n %Output:\n out =\n\n 1 2 3 4 4\n 1 2 3 5 3\n 1 2 4 5 3\n 1 3 4 5 3\n 2 3 4 5 3\n %So the first to the fourth column are the four number that were found to repeat in rows of matrix p (any and all combination that can appear in the rows of the matrix p). The fifth column is the amount of times the that particular set of matrix out(?,1:4) appear in matrix p. for for row one in matrix out, 1,2,3 and 4 in any combination appear 4 time in the rows of matrix p.\n\n So more examples...\n\n p = [1 2 3 4 9;\n 2 3 1 4 8]\n v = 4;\n\n out =\n 1 2 3 4 2\n %so any combination of 1,2,3 and 4 appear 2 times in matrix p\n\n and another:\n\n p = [1 2 3 4 9;\n 2 3 1 4 8;\n 3 4 2 7 1]\n v = 3;\n\n out =\n 1 2 3 3\n 1 2 4 3\n 1 3 4 3\n 2 3 4 3\n %so this uses any combo of 3 values, so in this case out(?,1:3) are the number combos that can be found in matrix p, and the out(?,4) is the amount of times that those combos are found\n\n last example:\n\n p = [1 2 3 4 9;\n 2 3 1 4 8]\n v = 2;\n\n out =\n 1 2 2\n 1 3 2\n 1 4 2\n 2 3 2\n 2 4 2\n 3 4 2\n %so in this case only combos of out(?,1:2) are found and out(?,3) is the amounts of times that combo of out(?,1:2) is found in matrix p. so row four of matrix out (so out(4,:)...) shows that the combo of 2 and 3 are found 2 times in matrix p.]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>NOTE: only display any row number combos that occur at least 2 times or more!</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>I hope I gave enough instructions and explanation, if not please let me know and I will add to it! Thanks and good luck!</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

所以我认为这可能是一个艰难的人，可能只是对我很难！所以这就是它是什么，我会给一个矩阵，用一些行用5列，使它更简单，我不会在单行中重复任何数字单行，所以所有数字都在单行是唯一的。因此，您需要查找在单行中找到的2,3或4个数字，该数字在其他行中重复，它们在给定矩阵中重复的次数。为了使它更好一点，你只需要到重复在租赁两次或更多显示行/数字。示例是显示该做什么的最佳方法： <pre>％p是给定的矩阵p = [1 2 3 4 5;2 3 4 5 1;3 4 6 7 8;1 2 4 3 5;4 6 3 2 1];％v是被检查的每行的元素量，以查看它们是否在另一行v = 4中重复; %Output: out =</pre><pre> 1 2 3 4 4 1 2 3 5 3 1 2 4 5 3 1 3 4 5 3 2 3 4 5 3 %So the first to the fourth column are the four number that were found to repeat in rows of matrix p (any and all combination that can appear in the rows of the matrix p). The fifth column is the amount of times the that particular set of matrix out(?,1:4) appear in matrix p. for for row one in matrix out, 1,2,3 and 4 in any combination appear 4 time in the rows of matrix p.</pre><pre> So more examples...</pre><pre> p = [1 2 3 4 9; 2 3 1 4 8] v = 4;</pre><pre> out = 1 2 3 4 2 %so any combination of 1,2,3 and 4 appear 2 times in matrix p</pre><pre> and another:</pre><pre> p = [1 2 3 4 9; 2 3 1 4 8; 3 4 2 7 1] v = 3;</pre><pre> out = 1 2 3 3 1 2 4 3 1 3 4 3 2 3 4 3 %so this uses any combo of 3 values, so in this case out(?,1:3) are the number combos that can be found in matrix p, and the out(?,4) is the amount of times that those combos are found</pre><pre> last example:</pre><pre> p = [1 2 3 4 9; 2 3 1 4 8] v = 2;</pre><pre> out = 1 2 2 1 3 2 1 4 2 2 3 2 2 4 2 3 4 2 %so in this case only combos of out(?,1:2) are found and out(?,3) is the amounts of times that combo of out(?,1:2) is found in matrix p. so row four of matrix out (so out(4,:)...) shows that the combo of 2 and 3 are found 2 times in matrix p.</pre>NOTE: only display any row number combos that occur at least 2 times or more!I hope I gave enough instructions and explanation, if not please let me know and I will add to it! Thanks and good luck!

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克里斯·E.2013年7月25日

这就是聪明！

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