Problem 44. Trimming Spaces

Isn't the use of regexp or regexprep supposed to be limited? It's not that I dislike using it, it's just that these string problems seem to be becoming a regexprep practice.

中间没有多个空间的测试用例。我曾考虑过strjoin（strsplit），如果您从strsplit操作中删除了空单元，它将通过此​​处的所有测试，但是它会将中间的多个空间减少到一个。

I am sure that there is a more efficient way to perform this operation with just regexp, but the intricacies of this wonderful function still elude me.

如果您有MATLAB> = 2016b

i do not understand what the solution of test 5 should be, or why my solution is wrong

One line

Keeps failing test 5 because pretty much all Matlab functions treat \t as space. Tried strtrim(a), isspace(a(i)) = 1, textscan(a,'%s').
The only thing that picks it up is isequal(a(1),' ') = 0. So, only brute force loop can pass test 5.
Not worth the effort.

Test case 5 is failing for strtrim(str) or isspace(str) functions - both consider \t as space.

Would fail for double spaces within string

查看“锚”表达式$和 ^。

How is this able to pass test 5? It should remove the leading tab and fail.

check the test 5????