The average slope of the two lines suggest that in one case you are integrating the accelartion into velocity (orangeFRF) so you are plotting somthing like (m/s)/N (this aspect could be confimed also by the 3 order of magnitude).
While in the second case (blueFRF) it seems that you are plotting the "accelerance" in g/N.
如果您想检查此方面，只需计算以下内容：
blueFRF / ( j*omega )％整合加速度（bluefrf）[（m/s^2）]一次，以获取[（m/s）/n]中测量速度（OrangeFRF）
Theoretically you should get the orangeFRF. You can also compute the viceversa, so orangeFRF * ( j*omega )
I check my theory at 10Hz by hands, and the result confirm what I suspect:
2e-2/（2*pi*10）^2 = 5.0661E-006％由于我们正在研究规模，因此我们可以考虑j。如果您也对阶段感兴趣，请考虑j。
因此，您可能必须注意将AcceleranceFRF的整合到VelocityFRF中。
Check more carefully this aspect and let me know.
Morover，当您计算FRF时，不要忘记将窗户应用于原始信号。我注意到您正在使用Hann窗口，但是如果您选择了正确的窗口，请检查最新状态。通常，对于带有撞击锤的FRF，最好在两个信号上应用指数窗口。如果您使用来自恒定源的随机噪声（例如电动力振荡器），则最好使用Hann窗口。
Last point, don't forget to check the coherence of your FRF that gives you info about the quality of your measurements. The command "
modalfrf
”也给你这个输出。看医生了info.
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Best regards
