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Linear Elasticity Equations

Summary of the Equations of Linear Elasticity

The stiffness matrix of linear elastic isotropic material contains two parameters:

  • E, Young's modulus (elastic modulus)

  • ν, Poisson’s ratio

Define the following quantities.

σ = stress f = body force ε = strain u = displacement

The equilibrium equation is

· σ = f

The linearized, small-displacement strain-displacement relationship is

ε = 1 2 ( u + u T )

The balance of angular momentum states that stress is symmetric:

σ i j = σ j i

The Voigt notation for the constitutive equation of the linear isotropic model is

[ σ 11 σ 22 σ 33 σ 23 σ 13 σ 12 ] = E ( 1 + ν ) ( 1 2 ν ) [ 1 ν ν ν 0 0 0 ν 1 ν ν 0 0 0 ν ν 1 ν 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 0 1 2 ν ] [ ε 11 ε 22 ε 33 ε 23 ε 13 ε 12 ]

The expanded form uses all the entries inσandεtakes symmetry into account.

[ σ 11 σ 12 σ 13 σ 21 σ 22 σ 23 σ 31 σ 32 σ 33 ] = E ( 1 + ν ) ( 1 2 ν ) [ 1 ν 0 0 0 ν 0 0 0 ν 1 2 ν 0 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 1 ν 0 0 0 ν 1 2 ν 0 0 0 1 2 ν 0 0 1 2 ν 0 1 ν ] [ ε 11 ε 12 ε 13 ε 21 ε 22 ε 23 ε 31 ε 32 ε 33 ] (1)

在前面的图中,信谊•意味着条目metric.

3D Linear Elasticity Problem

The toolbox form for the equation is

· ( c u ) = f

But the equations in the summary do not have ∇ualone, it appears together with its transpose:

ε = 1 2 ( u + u T )

It is a straightforward exercise to convert this equation for strainεto ∇u. In column vector form,

u = [ u x / x u x / y u x / z u y / x u y / y u y / z u z / x u z / y u z / z ]

Therefore, you can write the strain-displacement equation as

ε = [ 1 0 0 0 0 0 0 0 0 0 1 2 0 1 2 0 0 0 0 0 0 0 1 2 0 0 0 1 2 0 0 0 1 2 0 1 2 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 2 0 1 2 0 0 0 1 2 0 0 0 1 2 0 0 0 0 0 0 0 1 2 0 1 2 0 0 0 0 0 0 0 0 0 1 ] u A u

whereAstands for the displayed matrix. So rewritingEquation 1, and recalling that • means an entry is symmetric, you can write the stiffness tensor as

σ = E ( 1 + ν ) ( 1 2 ν ) [ 1 ν 0 0 0 ν 0 0 0 ν 1 2 ν 0 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 0 1 2 ν 0 0 0 0 0 1 ν 0 0 0 ν 1 2 ν 0 0 0 1 2 ν 0 0 1 2 ν 0 1 ν ] A u = E ( 1 + ν ) ( 1 2 ν ) [ 1 ν 0 0 0 ν 0 0 0 ν 0 1 / 2 ν 0 1 / 2 ν 0 0 0 0 0 0 0 1 / 2 ν 0 0 0 1 / 2 ν 0 0 0 1 / 2 ν 0 1 / 2 ν 0 0 0 0 0 ν 0 0 0 1 ν 0 0 0 ν 0 0 0 0 0 1 / 2 ν 0 1 / 2 ν 0 0 0 1 / 2 ν 0 0 0 1 / 2 ν 0 0 0 0 0 0 0 1 / 2 ν 0 1 / 2 ν 0 ν 0 0 0 ν 0 0 0 1 ν ] u

Make the definitions

μ = E 2 ( 1 + ν ) λ = E ν ( 1 + ν ) ( 1 2 ν ) E ( 1 ν ) ( 1 + ν ) ( 1 2 ν ) = 2 μ + λ

and the equation becomes

σ = [ 2 μ + λ 0 0 0 λ 0 0 0 λ 0 μ 0 μ 0 0 0 0 0 0 0 μ 0 0 0 μ 0 0 0 μ 0 μ 0 0 0 0 0 λ 0 0 0 2 μ + λ 0 0 0 λ 0 0 0 0 0 μ 0 μ 0 0 0 μ 0 0 0 μ 0 0 0 0 0 0 0 μ 0 μ 0 λ 0 0 0 λ 0 0 0 2 μ + λ ] u c u

If you are solving a 3-D linear elasticity problem by usingPDEModelinstead ofStructuralModel, use theelasticityC3D(E,nu)function (included in your software) to obtain theccoefficient. This function uses the linearized, small-displacement assumption for an isotropic material. For examples that use this function, seeStationaryResults.

Plane Stress

Plane stress is a condition that prevails in a flat plate in thex-yplane, loaded only in its own plane and withoutz-direction restraint. For plane stress,σ13=σ23=σ31=σ32=σ33= 0. Assuming isotropic conditions, the Hooke's law for plane stress gives the following strain-stress relation:

[ ε 11 ε 22 2 ε 12 ] = 1 E [ 1 ν 0 ν 1 0 0 0 2 + 2 ν ] [ σ 11 σ 22 σ 12 ]

Inverting this equation, obtain the stress-strain relation:

( σ 11 σ 22 σ 12 ) = E 1 ν 2 ( 1 ν 0 ν 1 0 0 0 1 ν 2 ) ( ε 11 ε 22 2 ε 12 )

Convert the equation for strainεto ∇u.

ε = [ 1 0 0 0 0 1 2 1 2 0 0 1 2 1 2 0 0 0 0 1 ] u A u

Now you can rewrite the stiffness matrix as

[ σ 11 σ 12 σ 21 σ 22 ] = [ E 1 ν 2 0 0 E ν 1 ν 2 0 E 2 ( 1 + ν ) E 2 ( 1 + ν ) 0 0 E 2 ( 1 + ν ) E 2 ( 1 + ν ) 0 E ν 1 ν 2 0 0 E 1 ν 2 ] u = [ 2 μ ( μ + λ ) 2 μ + λ 0 0 2 λ μ 2 μ + λ 0 μ μ 0 0 μ μ 0 2 λ μ 2 μ + λ 0 0 2 μ ( μ + λ ) 2 μ + λ ] u

Plane Strain

Plane strain is a deformation state where there are no displacements in thez-direction, and the displacements in thex- andy-directions are functions ofxandybut notz. The stress-strain relation is only slightly different from the plane stress case, and the same set of material parameters is used.

For plane strain,ε13=ε23=ε31=ε32=ε33= 0. Assuming isotropic conditions, the stress-strain relation can be written as follows:

( σ 11 σ 22 σ 12 ) = E ( 1 + ν ) ( 1 2 ν ) ( 1 ν ν 0 ν 1 ν 0 0 0 1 2 ν 2 ) ( ε 11 ε 22 2 ε 12 )

Convert the equation for strainεto ∇u.

ε = [ 1 0 0 0 0 1 2 1 2 0 0 1 2 1 2 0 0 0 0 1 ] u A u

Now you can rewrite the stiffness matrix as

[ σ 11 σ 12 σ 21 σ 22 ] = [ E ( 1 ν ) ( 1 + ν ) ( 1 2 ν ) 0 0 E ν ( 1 + ν ) ( 1 2 ν ) 0 E 2 ( 1 + ν ) E 2 ( 1 + ν ) 0 0 E 2 ( 1 + ν ) E 2 ( 1 + ν ) 0 E ν ( 1 + ν ) ( 1 2 ν ) 0 0 E ( 1 ν ) ( 1 + ν ) ( 1 2 ν ) ] u = [ 2 μ + λ 0 0 λ 0 μ μ 0 0 μ μ 0 λ 0 0 2 μ + λ ] u