我认为这就是你的意思,
为nn = 1: N
ynn = y (nn);
有趣= @ (x) (√(x (1) - a) ^ 2 + (x (2) - b) ^ 2) + sqrt ((x (1) - c) ^ 2 + (x (2) - d) ^ 2)) ^ 2 - (ynn) ^ 2) ^ 2
= @监狱(x) nonlcon (x, ynn h g);
xopt = fmincon (Aeq有趣,x0, A, b,说真的,磅,乌兰巴托,反对);
结束
函数测查[c] = nonlcon (x, y, h, g)
c =√(x (1) - h) ^ 2 + (x (2) - g) ^ 2) - y;
测查= [];
结束
