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Maria ines Barba Sarasua
Maria ines Barba Sarasua 2023年5月31日
回答: 沃尔特·罗伯森 2023年5月31日
跑:
你好,我有一个错误:
无法执行任务,因为指数左边与右边的大小不兼容。
错误 信谊/ privsubsasgn ( 第1229行 )
L_tilde2 =内装式(subsasgn, L_tilde、结构(“类型”,“()”,“潜艇”,{变长度输入宗量}),R_tilde);
错误 信谊/ subsasgn ( 第1060行 )
C = privsubsasgn (L R第1 {:});
我的代码如下:
清晰的所有
clc
信谊x
e-05尾= (5.93266,0.00082573,0.001571951,0.002318172,0.003064541,0.004018053,0.00493061,0.005552929,0.006549172,0.007338123,0.008085823,0.008833522,0.009415033,0.009996545,0.010868442,0.011574151,0.012196174,0.013025341,0.013895908,0.014848681,0.015801455,0.017251758,0.018371164,0.019200479,0.019781399,0.02036254,0.020860957,0.021234807,0.021691677);
人= (1.638232756,1.618669688,1.579773777,1.540877866,1.496456555,1.446449258,1.379877876,1.329967516,1.230219498,1.141582866,1.047432951,0.953283036,0.881283191,0.809283346,0.71509708,0.643060884,0.604201324,0.559755779,0.515298116,0.492917821,0.470537526,0.420384823,0.359278257,0.309307311,0.259409068,0.201222724,0.140297914,0.093222956,0.037835664);
v_c = 0.0000174/1.19;
A_disipador = 0.095 * 0.002 * 45;
为M = 1:元素个数(尾)
V_Disipador =(尾/ A_disipador);
Re = (V_Disipador * 0.039) / (v_c);
f (M) = vpasolve ((1 /√(x) = = 2 *日志((0.502/0.095)/ 3.7 + 2.51 /(重新(M) * sqrt (x)))))%这是错误的
h = f * (0.095/0.0039) * ((1.3048) ^ 2 / (2 * 9.81))。
结束
无法执行任务,因为指数左边与右边的大小不兼容。

信谊误差/ privsubsasgn(第1168行)
L_tilde2 =内装式(subsasgn, L_tilde、结构(“类型”,“()”,“潜艇”,{变长度输入宗量}),R_tilde);

错误索引(第999行)
C = privsubsasgn (L R第1 {:});

在回答这个问题。

接受的答案

沃尔特·罗伯森
沃尔特·罗伯森 2023年5月31日
跑:
信谊x
e-05尾= (5.93266,0.00082573,0.001571951,0.002318172,0.003064541,0.004018053,0.00493061,0.005552929,0.006549172,0.007338123,0.008085823,0.008833522,0.009415033,0.009996545,0.010868442,0.011574151,0.012196174,0.013025341,0.013895908,0.014848681,0.015801455,0.017251758,0.018371164,0.019200479,0.019781399,0.02036254,0.020860957,0.021234807,0.021691677);
v_c =符号(0.0000174)/信谊(1.19);
A_disipador =符号(0.095)*信谊(0.002)*符号(45);
为M = 1:元素个数(尾)
V_Disipador =(尾(M) / A_disipador);
Re = (V_Disipador *信谊(0.039))/ (v_c);
eqn = (1 /√(x) = = 2 *日志((信谊(0.502)/信谊(0.095))/信谊(3.7)+符号(2.51)/ (Re * sqrt (x))))
f {M} = vpasolve (eqn);%这是错误的
M h {M} = f{} *(信谊(0.095)/信谊(0.0039))*(信谊(1.3048)^ 2 /(2 *信谊(9.81)));
结束
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f
f =1×29单元阵列
列1到15 {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym}列16到29日{0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym} {0×1 sym}
看看方程。日志()内的潦倒常数又补充说,所以提供了比除以sqrt (x)并不是消极的,那么日志()内的值必须大于1,所以日志必须是积极的。积极的日志乘以- 2是负的,然后如果x是积极sqrt (x)是永远- 1 /√(x)从来不是消极的。我们得出这样的结论,如果x是正数,那么方程不能持有。
如果x是-什么?然后sqrt (x)将复杂的价值,你会以日志的一个复杂的价值和试图匹配1 /√(- x)。这些可以等于多少?我不怀疑,但是我还没有研究证明了这一点。

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