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How can I assign several values from cell-array tovariables?

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Diego R
Diego R on 4 Sep 2019
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Answered: Diego Ron 5 Sep 2019
I have the cell array from the example:
myNum = [1, 2, 3]; myCell = {'one','two'}; myStruct.Field1 = ones(3); myStruct.Field2 = 5*ones(5);
C = {100 * myNum myNum;myCell, myStruct}
C = 2x2 cell array
{1x3 double} {1x3 double}
{1x2 cell } {1x1 struct}
I want to receive:
a=1
b=2
c=3
I've tried to do these, but didn't work:
[a,b,c]=C{1,1}
[a,b,c]=deal(C{1,1}(1,:))
I need to do in one time because my real code has dozens of values.
Thanks in advance for answers.

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Accepted Answer

Kelly Kearney
Kelly Kearney on 4 Sep 2019
我认为你会需要使用一个快速的媒介物te variable so you can convert the numeric array to a comma-separated list:
tmp = num2cell(C{1,1});
[a,b,c] = deal(tmp{:})
1 Comment
Star Strider
Star Strider on 5 Sep 2019
In more recent MATLAB releases, deal isn’t necessary.
Just use:
[a,b,c] = tmp{:}

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More Answers (2)

Walter Roberson
Walter Roberson on 5 Sep 2019
Unfortunately the temporary variable is still a practical necessity. It can be done away with, at cost:
[a,b,c] = subsref(num2cell(C{1,1}), struct('type','{}','subs', {{':'}}))
but it becomes a lot easier if you define
VECEXPAND = @(VEC) VEC{:};
DEALVEC = @(VEC) VECEXPAND(num2cell(VEC));
[a, b, c] = DEALVEC(C{1,1})
Diego R
Diego R on 5 Sep 2019
Thanks a lot. It works. But it is a shame there isn't a direct way.

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