质量守恒说在=。的初始高度1米Vr0 = Vr_max * (h0 / hr_dam) ^ 0.3 = =
5.8419 e + 05
这是体积reservor在t = 0。我们也知道,dv / dt =给50 m ^ 3 / s流- q (t、h (t))的管和水坝。dh / dt是解决通过Vr0和改变t dh产生dh = nthroot ((VR + Q_in-Qout) / Vr0, 0.3)现在对任何体积coresponding h值。
% %储层质量守恒方程(溢洪道以下)
% dV / dt = Vr-max (h / hr_dam) ^ 0.3
Vr0 = Vr_max * (h0 / hr_dam) ^ 0.3
dh = h0;
t = 0: .01:10
Vr = Vr_max * (dh / hr_dam) ^ 0.3;
Qpipe = diff c₁* Ac *√(2 * g * dh));
Qwier = diff (c₁* Ac *√(2 * g * dh) + c₂* L_w * (dh-Hspill)。^ 3/2));
Q_out = Qpipe + Qwier;
dh = nthroot ((Vr + Q_in-Q_out) / Vr0, 0.3);
结束
就是我现在在它不工作。我想了解如何吉文斯等同起来。任何帮助将当然apriciated