t = 1/get（input1，'Freq'）；
Input1是一个丢失的变量/对象，因此您必须弄清楚。如果这是别人的代码，那么我的信息比您对此的信息少。
为了[i=0;1;1i
{
% ...
};
I have no idea what language this is from, but it's not MATLAB. I am not familiar with any 4-argument for loop syntax, so I have no idea what the 1 means. You're using i as both an integer index and you're attempting to explicitly use it as a complex number. Both i and j are sqrt(-1). Unless you're using them as that, don't cause problems by overloading them for use as indices or something.
b = wn*t*sqr（1-1/4/q/q）;
我假设应该是SQRT（）？
y = filter（input1，bb，aa）;
同样，我假设Input1是您已经存在的一些变量。
没有丢失的变量，这是我最好的猜测：
CLC;清晰
ymax = [];
ff = [];
fmin = 1;
fmax=1000;
n = 90;
qv =（fmax/fmin）^（1/n）;
％t = 1/get（input1，'freq'）;
t = 1/200;百分比的假号以使其运行
Q = 10;
为了k = 0：n-1％ 这是正确的吗？
fn = fmin*qv^k;
ff = [ff，fn];
wn = 2*pi*fn;
a = wn*t/2/q;
b = wn*t*sqrt（1-1/4/q/q）;
b0 = 1-exp（-a）*sin（b）/b;
b1 = 2*exp（-a）*（sin（b）/b-cos（b））;
b2 = exp（（ - 2）*a）-exp（-a）*sin（b）/b;
a1 =（ - 2）*exp（（ - 1）*a）*cos（b）;
a2 = exp（（ - 2）*a）;
BB = [B0，B1，B2];
aa = [ - a1，-a2];
%y=filter(input1,BB,AA);
y =过滤器（BB，BB，AA）;％只是塞进其中的东西，所以它运行
yy = max（y）;
ymax = [ymax，yy];
结尾
