问题33.创建时间表

good problem

I agree

moderately easy nice.

Challenging

That one was unique

m = [1:n]'*[1:n];

K = kron(1:n,1:n)
m = reshape(K,n,n)

Good Problem

m =（1：n）'*（1：n）;

m = [1:n]'*[1:n];

what is the true leading solution?

谢谢道格

I think the error is pretty clear. line3: column=1:1:n; line4:row=1:1:n.
besides, 1:n just fine, the "1" in the middle is quite not necessary.

如果我使用1：n和1：1：n？两者都是相同的呢？两种情况的步长为1。尝试了您所说的话，但试件再次失败

two equal sign in line 3&4 are missed: this is fatal error, fix that, in my computer seems work fine. and 1:n is another problem, it can pass even you don't change it. nontheless, 1 in the middle is redundant. it CAN be removed, not like you have to.

你怎么能解决这个10码?

hahahaha,hello~~

very easy

好的

On my matlab this code works for all the test, but here it fails, why?
m = reshape(1:n^2,[n,n])';

此外，我如何才能看到我解决的问题的更好解决方案，以提高我的M万博 尤文图斯ATLAB技能？

Thank you very much for your attention

Sorry, I missed a ;-)

是的，我做到了。

Test solution 2 is incorrect, should be:

y_correct = [1 2 3; 2 4 6; 3 6 9]

current solution isn't even square...

The test suite is broken for this problem.

The second test should say y_correct = [1 2 3; 2 4 6;3 6 9];

can someone please tell me what I've done wrong here pls. Thanks

You've done nothing wrong; the solution to Test Suite #2 is incorrect.

No need to apply loop here, m=[1:n]'*[1:n] works fine.
function m = timestables(n)
m=(1:n)'*(1:n);
end

test # 2 is wrong, as it should be a 3x3 matrix,
y_correct for x=3 is:
[1 2 3; 2 4 6; 3 6 9]

Test nr. 2 seems not right: the soluton for x= 3 should be:
y_correct = [1 2 3; 2 4 6; 3 6 9]

lol

我尝试了MATLAB，它可以正常工作。

this solution is correct... the answer for test #2 is incorrect.

好问题。很好的提醒矢量乘法如何工作。

Good

Pretty Cool

Duh! Thanks for reminding me how matrix multiplication works

很好地学习矩阵标量乘法

it's correct for any value !!!!!

What, this is so weird!!!! Nice job

Missing semicolons...

l just wonder is it a real boring thing (times table),that we need to program it,for exam.12*12=144,almost everybody who atteded high school can answer,2^10=1024;25*25=625,13*13=169;14*14=196;15*15=225;it is such an easy thing that we needn't to make a table,we can calculate it out once we see such an multiplication

like your solution its very concise but there is one problem for me you have used '* for multiplication, can you please tell why?

function m = timestables(n)
for i=1:n
j = 1：n
m(i,j)=i*j;
end
end
%apparently this doesn't work even though MatLab says it works for any size

Brilliant!

After the solution I come up with ends up in the middle of the graph I feel disappointed. But then I learn there's a command that does something I didn't know about and I feel better about myself because I learned a new command!

amazing!

very elegant :)

好的:)

interesting approach, very smart!