eqn =
                       $$\mathrm{一个}{x}^2+bx+c＝0$$

S =

                       

                        $$（\begin{array}{c}-\frac{b+\sqrt{b^2-4\mathrm{一个}c}}{2\mathrm{一个}}\\ -\frac{b-\sqrt{b^2-4\mathrm{一个}c}}{2\mathrm{一个}}\end{array}）$$
                      

Sa =

                       

                        $$-\frac{c+bx}{x^2}$$
                      

S =

                       

                        $$\begin{array}{l}（\begin{array}{c}5\\ -{\sigma }_1-\frac{5}{4}-\frac{5\sqrt{2}\sqrt{5-\sqrt{5}}\mathrm{我}}{4}\\ -{\sigma }_1-\frac{5}{4}+\frac{5\sqrt{2}\sqrt{5-\sqrt{5}}\mathrm{我}}{4}\\ {\sigma }_1-\frac{5}{4}-\frac{5\sqrt{2}\sqrt{\sqrt{5}+5}\mathrm{我}}{4}\\ {\sigma }_1-\frac{5}{4}+\frac{5\sqrt{2}\sqrt{\sqrt{5}+5}\mathrm{我}}{4}\end{array}）\\ \\ \mathrm{在哪里}\\ \\ \mathrm{}{\sigma }_1＝\frac{5\sqrt{5}}{4}\end{array}$$
                      

S =
                       $$5$$

S =带有字段的结构:U: 1/3 v: -2/3

ans =

                       

                        $$\frac{1}{3.}$$
                      

ans =

                       

                        $$-\frac{2}{3.}$$
                      

e1 =

                       

                        $$\frac{1}{9}$$
                      

e2 =

                       

                        $$-\frac{5}{3.}$$
                      

S =空sym: 0-by-1

ans =

                       

                        $$\frac{\sqrt{u-3.v^2}}{2}-\frac{v}{2}$$
                      

ans =
                       $$v$$

ans =
                       $$（\begin{array}{cc}u& v\end{array}）$$

ans =
                       $$4v^2<u\wedge u<4\wedge 0<v$$

ans =逻辑1

xSol =

                       

                        $$\frac{\sqrt{11}}{4}-\frac{1}{4}$$
                      

ySol =

                       

                        $$\frac{1}{2}$$
                      

求解=

                       

                        $$（\begin{array}{c}-\frac{2}{3.}-\frac{\sqrt{2}\mathrm{我}}{3.}\\ -\frac{2}{3.}+\frac{\sqrt{2}\mathrm{我}}{3.}\end{array}）$$
                      

溶解=

                       

                        $$（\begin{array}{c}\frac{1}{3.}-\frac{\sqrt{2}\mathrm{我}}{3.}\\ \frac{1}{3.}+\frac{\sqrt{2}\mathrm{我}}{3.}\end{array}）$$
                      

万博 尤文图斯解决方案=

                       

                        $$（\begin{array}{cc}-\frac{2}{3.}-\frac{\sqrt{2}\mathrm{我}}{3.}& \frac{1}{3.}-\frac{\sqrt{2}\mathrm{我}}{3.}\\ -\frac{2}{3.}+\frac{\sqrt{2}\mathrm{我}}{3.}& \frac{1}{3.}+\frac{\sqrt{2}\mathrm{我}}{3.}\end{array}）$$
                      

solx =
                       $$\pi k$$

参数=
                       $$k$$

条件=
                       $$k\in \mathbb{Z}$$

solk =
                       $$1$$

valx =
                       $$\pi$$

ans =逻辑1

valx =
                       $$4\pi$$

ans =
                       $$12.566370614359172953850573533118$$

S =
                       $$1$$

S =

                       

                        $$（\begin{array}{c}-6\\ 1\end{array}）$$
                      

ans =

                       

                        $$（\begin{array}{c}根（z^{3.}+z^2+\mathrm{一个}，z，1）\\ 根（z^{3.}+z^2+\mathrm{一个}，z，2）\\ 根（z^{3.}+z^2+\mathrm{一个}，z，3.）\end{array}）$$
                      

S =

                       

                        $$\begin{array}{l}（\begin{array}{c}\frac{1}{9{\sigma }_1}+{\sigma }_1-\frac{1}{3.}\\ -\frac{1}{18{\sigma }_1}-\frac{{\sigma }_1}{2}-\frac{1}{3.}-\frac{\sqrt{3.}\left(\frac{1}{9{\sigma }_1}-{\sigma }_1\right)\mathrm{我}}{2}\\ -\frac{1}{18{\sigma }_1}-\frac{{\sigma }_1}{2}-\frac{1}{3.}+\frac{\sqrt{3.}\left(\frac{1}{9{\sigma }_1}-{\sigma }_1\right)\mathrm{我}}{2}\end{array}）\\ \\ \mathrm{在哪里}\\ \\ \mathrm{}{\sigma }_1＝{\left(\sqrt{{\left(\frac{\mathrm{一个}}{2}+\frac{1}{27}\right)}^2-\frac{1}{729}}-\frac{\mathrm{一个}}{2}-\frac{1}{27}\right)}^{1/3.}\end{array}$$
                      

S =

                       

                        $$（\begin{array}{c}0\\ \frac{\pi }{6}\\ \frac{5\pi }{6}\end{array}）$$
                      

S1 =
                       $$0$$